1. ∫ (1/3 ×^3+×^2-1)= ∫ (1/3 ×^3)dx +∫(×^2)dx -∫1dx = 1/12 x^4 + 1/3 x^3 - x + C
2. ∫ (2-8× cos4×dx= ∫ 2 cos4×dx - ∫8×cos4×dx = 1/2 sin 4x - 2xsin4x - 2cos4x +C
3. lim(×→0) ×/(∛(8-×-∛(8+×= lim(×→0) ×(∛(8-×+∛(8+× / ( (∛(8-×-∛(8+× (∛(8-×+∛(8+× ) = lim(×→0) ×( ∛( 8-×+∛(8+× / -2x = (∛8 + ∛8) / -2 = - ∛8
проверено: 1 - верно, 2 и 3 - неверно