а) lim(x->00) (2x^3+x^2-5)/(x^3+x-2)=(x^3(2+1/x-5/x^3))/(x^3(1+1/x^2-2/x^3))=(2+1/x-5/x^3)/(1+1/x^2-2/x^3)=
=2/1=2
б)lim(x->1) (x-sqrt(x))/(x^2-x)=(xsqrt(x)-x)/(x^2sqrt(x)-xsqrt(x))=(sqrt(x)-1)/(xsqrt(x)-sqrt(x))=(sqrt(x)-1)/(sqrt(x)(sqrt(x)-1)(sqrt(x)+1)=1/(x+sqrt(x)) при x ->1 = 1/2
в)lim(x->0) sqrt(1-cos2x)/x(по модулю)=((sqrt(1-cos2x)/sqrt(2))/(x/sqrt(2))=sqrt((1-cos2x)/2)/(x/sqrt(2))=sqrt(sin^2x)/(x/sqrt(2))=sqrt(2sin^2x)/x=sqrt(2x^2)/x=xsqrt(2)/x=sqrt(2)
г)lim(x->00) ((4x+1)/(4x))^(2x)=((4x+1+1)/(4x+1))^(2x)=(1+(1)/(4x+1))^(2x)=(1+1/y)^(1/2y-1/2)=?...
помогите проверить и решить